(1/x-1)=(2/x^2)

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Solution for (1/x-1)=(2/x^2) equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x-1 = 2/(x^2) // - 2/(x^2)

1/x-(2/(x^2))-1 = 0

1/x-2*x^-2-1 = 0

x^-1-2*x^-2-1 = 0

t_1 = x^-1

1*t_1^1-2*t_1^2-1 = 0

t_1-2*t_1^2-1 = 0

DELTA = 1^2-(-2*(-1)*4)

DELTA = -7

DELTA < 0

x belongs to the empty set

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